使用用户定义的函数检查素数或阿姆斯壮数. C

#c #数字

#include <math.h>
#include <stdio.h>

int checkPrimeNumber(int n);
int checkArmstrongNumber(int n);

int main() {
   int n, flag;
   printf("Enter a positive integer: ");
   scanf("%d", &n);

flag = checkPrimeNumber(n);
   if (flag == 1)
      printf("%d is a prime number.\n", n);
   else
      printf("%d is not a prime number.\n", n);

flag = checkArmstrongNumber(n);
   if (flag == 1)
      printf("%d is an Armstrong number.", n);
   else
      printf("%d is not an Armstrong number.", n);
   return 0;
}

int checkPrimeNumber(int n) {
   int i, flag = 1, squareRoot;

squareRoot = sqrt(n);
   for (i = 2; i <= squareRoot; ++i) {
      if (n % i == 0) {
         flag = 0;
         break;
      }
   }
   return flag;
}

int checkArmstrongNumber(int num) {
   int originalNum, remainder, n = 0, flag;
   double result = 0.0;

for (originalNum = num; originalNum != 0; ++n) {
      originalNum /= 10;
   }

for (originalNum = num; originalNum != 0; originalNum /= 10) {
      remainder = originalNum % 10;

result += pow(remainder, n);
   }

if (round(result) == num)
      flag = 1;
   else
      flag = 0;
   return flag;
}

Output result

Enter a positive integer: 407
407 is not a prime number.
407 is an Armstrong number.

C

C 语言中的代码示例和问题解答

使用用户定义的函数检查素数或阿姆斯壮数. C

C

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