የአናባቢዎች፣ ተነባቢዎች እና የመሳሰሉትን ብዛት ይቁጠሩ. C

#c #መቁጠር

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#include <stdio.h>
int main() {
    char line[150];
    int vowels, consonant, digit, space;
​
    vowels = consonant = digit = space = 0;
​
    printf("Enter a line of string: ");
    fgets(line, sizeof(line), stdin);
​
    for (int i = 0; line[i] != '\0'; ++i) {
        if (line[i] == 'a' || line[i] == 'e' || line[i] == 'i' ||
            line[i] == 'o' || line[i] == 'u' || line[i] == 'A' ||
            line[i] == 'E' || line[i] == 'I' || line[i] == 'O' ||
            line[i] == 'U') {
            ++vowels;
        } else if ((line[i] >= 'a' && line[i] <= 'z') || (line[i] >= 'A' && line[i] <= 'Z')) {
            ++consonant;
        } else if (line[i] >= '0' && line[i] <= '9') {
            ++digit;
        } else if (line[i] == ' ') {
            ++space;
        }
    }
​
    printf("Vowels: %d", vowels);
    printf("\nConsonants: %d", consonant);
    printf("\nDigits: %d", digit);
    printf("\nWhite spaces: %d", space);
    return 0;
}

Output result

Enter a line of string: adfslkj34 34lkj343 34lk
Vowels: 1
Consonants: 11
Digits: 9
White spaces: 2

C

ኮድ ምሳሌዎች እና ለጥያቄዎች መልስ በ C programming luaguage

የአናባቢዎች፣ ተነባቢዎች እና የመሳሰሉትን ብዛት ይቁጠሩ. C

C

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